Which specific mode of radioactive decay always produces a daughter nuclide that is an "isodiaphere" — Nuclear Chemistry and Radioactivity Chemistry Question

💡 Solution & Explanation

An $\alpha$ -emission reduces the mass number ($A$) by $4$ and atomic number ($Z$) by $2$. The new isotopic number is $(A-4) - 2(Z-2) = A - 4 - 2Z + 4 = A - 2Z$. Since the value $A - 2Z$ remains constant, they are isodiaphers.