If a radioactive nucleus possesses an ratio that is too high (placing it above the belt of stability β Nuclear Chemistry and Radioactivity Chemistry Question
Question
If a radioactive nucleus possesses an $n/p$ ratio that is too high (placing it above the belt of stability), it will typically undergo spontaneous decay by emitting:
Answer: B
π‘ Solution & Explanation
A nucleus above the stability belt has an excess of neutrons. To lower its $n/p$ ratio and achieve stability, it converts a neutron into a proton and an electron, ejecting the electron as a $\beta^-$ -particle.
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