A highly unstable parent nucleus undergoes two successive emissions to form the stable isotope Nitrogen-14 (). What was the atomic number () and mass number () of the original parent?

Question

A highly unstable parent nucleus undergoes two successive $\beta^-$ emissions to form the stable isotope Nitrogen-14 (${}_{7}^{14}N$). What was the atomic number ($Z$) and mass number ($A$) of the original parent?

Prashant Kotian · Accepted Answer

Correct answer: A. Each -emission increases the atomic number by while keeping the mass number constant. If two -emissions yield , the parent must have had . The mass number remains .

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