According to the Group Displacement Law (Rutherford-Soddy rules), what is the net periodic table shi — Nuclear Chemistry and Radioactivity Chemistry Question
Question
According to the Group Displacement Law (Rutherford-Soddy rules), what is the net periodic table shift of a daughter element formed by the successive emission of one $\alpha$ -particle and two $\beta^-$ -particles from a parent nucleus?
Answer: D
💡 Solution & Explanation
One $\alpha$ -emission reduces the atomic number ($Z$) by 2. Two subsequent $\beta^-$ -emissions increase $Z$ by a total of 2. The net change in $Z$ is zero, meaning the final product is an isotope of the parent element and occupies the identical group.
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