In the Uranium series, decays through a succession of steps to finally yield the stable isotope . Calculate the exact total number of and particles emitted during this complete decay process.

Question

In the Uranium series, ${}_{92}^{238}U$ decays through a succession of steps to finally yield the stable isotope ${}_{82}^{206}Pb$. Calculate the exact total number of $\alpha$ and $\beta^-$ particles emitted during this complete decay process.

Prashant Kotian · Accepted Answer

Correct answer: A. . Number of -particles = . Expected after = . Actual final . Difference = . Since each increases by 1, there are particles.

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