The disintegration series (Thorium series) begins with Thorium-232 (). Which of the following stable β Nuclear Chemistry and Radioactivity Chemistry Question
Question
The $4n$ disintegration series (Thorium series) begins with Thorium-232 (${}_{90}^{232}Th$). Which of the following stable isotopes represents the final end product of this specific series?
Answer: C
π‘ Solution & Explanation
The mass numbers of all members in the $4n$ series are divisible by 4. $208/4 = 52$ exactly. Lead-208 is the final stable product of the Thorium series.
π¬Ask on WhatsApp β
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp β gets answered in minutes