The number of primary (), secondary () and tertiary () carbon atoms in toluene is given by the set: — IUPAC and Nomenclature Chemistry Question
Question
The number of primary ($1^\circ$), secondary ($2^\circ$) and tertiary ($3^\circ$) carbon atoms in toluene is given by the set:
Answer: B
💡 Solution & Explanation
Toluene ($C_6H_5CH_3$) contains one $1^\circ$ carbon (the methyl group), five $2^\circ$ carbons (the unsubstituted ring carbons), and one $3^\circ$ carbon (the ring carbon attached to the methyl group).
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