Determine the total number of pi () bonds present in one molecule of Hepta-1,6-dien-3-yne. — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

The structure contains two double bonds ("dien") and one triple bond ("yne"). Each double bond possesses 1 $\pi$ bond ($2 \times 1 = 2$). The triple bond possesses 2 $\pi$ bonds. Total $\pi$ bonds = $2 + 2 = 4$.