Pentane-2,3,4-triol () is symmetrical with an odd number of chiral centers (). How many strictly opt — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

For symmetrical systems possessing an odd number of chiral centers, the formula isolating strictly the meso compounds is $2^{(n-1)/2}$. Substituting $n=3$, the calculation becomes $2^{(3-1)/2} = 2^{2/2} = 2^1 = 2$. Therefore, exactly 2 distinct meso forms exist for pentane-2,3,4-triol.