What is the calculated Degree of Unsaturation (DU) for the highly substituted complex molecular form — Isomerism and Stereochemistry Chemistry Question
Question
What is the calculated Degree of Unsaturation (DU) for the highly substituted complex molecular formula $C_{12}H_{22}O_8N_3Br$, and what does this specific DU structurally permit?
Answer: B
💡 Solution & Explanation
The universal mathematical formula for Degree of Unsaturation is $DU = (C + 1) - (H + X - N) / 2$. Elements of the oxygen family (O, S) are strictly ignored in the calculation. Substituting the given values: $C=12$, $H=22$, $X=1$ (Bromine), $N=3$. $DU = (12 + 1) - (22 + 1 - 3) / 2 = 13 - (20 / 2) = 13 - 10 = 3$. A DU of 3 permits combinations like three double bonds, or one ring and two double bonds.
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