The dissociation constants of two acids and are and respectively. The relative strengths of the acid — Ionic Equilibrium Chemistry Question
Question
The dissociation constants of two acids $HA_1$ and $HA_2$ are $3.0 \times 10^{-4}$ and $1.8 \times 10^{-5}$ respectively. The relative strengths of the acids ($\text{Strength}_1 / \text{Strength}_2$) will be approximately:
Answer: B
💡 Solution & Explanation
Relative strength of weak acids is determined by the ratio of the square root of their dissociation constants: $\frac{\text{Strength}_1}{\text{Strength}_2} = \sqrt{\frac{K_{a1}}{K_{a2}}} = \sqrt{\frac{30 \times 10^{-5}}{1.8 \times 10^{-5}}} = \sqrt{\frac{30}{1.8}} = \sqrt{16.6} \approx 4.1$.
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