If HCl is diluted 100 times with pure water, what will be its approximate final pH? — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

Diluting $10^{-6} \text{ M }$ HCl 100 times gives $10^{-8} \text{ M }$ HCl. The pH of this extremely dilute acid is determined by factoring in water's $H^+$ contribution, yielding a pH slightly less than 7 (approx 6.98).