If 1 mL of 0.1 N HCl is added to 99 mL of an aqueous 0.1 N NaCl solution, what will be the pH of the — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

The NaCl solution is neutral. Adding 1 mL of 0.1 N HCl to make a total volume of 100 mL dilutes the acid 100 times. Final $[H^+] = \frac{0.1 \times 1}{100} = 10^{-3} \text{ N}$. Thus, pH = 3.0.