Equal volumes of three strong acid solutions of pH 3, 4, and 5 are mixed in a vessel. What will be t — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

$[H^+]_{mix} = \frac{10^{-3}V + 10^{-4}V + 10^{-5}V}{3V} = \frac{(100 + 10 + 1) \times 10^{-5}}{3} = \frac{111 \times 10^{-5}}{3} = 37 \times 10^{-5} = 3.7 \times 10^{-4} \text{ M}$.