Sodium bicarbonate () contains an amphiprotic anion. If and of carbonic acid are 6.3 and 10.3 respec — Ionic Equilibrium Chemistry Question
Question
Sodium bicarbonate ($NaHCO_3$) contains an amphiprotic anion. If $pK_{a1}$ and $pK_{a2}$ of carbonic acid are 6.3 and 10.3 respectively, what is the pH of a $0.1 \text{ M } NaHCO_3$ solution?
Answer: A
💡 Solution & Explanation
For amphiprotic anions, the pH is determined by $pH = (pK_{a1} + pK_{a2}) / 2$, which is independent of concentration. $pH = (6.3 + 10.3) / 2 = 16.6 / 2 = 8.3$.
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