When of () is added to of a saturated solution of (), what is the resultant concentration of in the — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

$CuCl$ provides $[Cl^-] = \sqrt{10^{-6}} = 10^{-3} \text{ M}$. Since $K_{sp}(CuCl) \gg K_{sp}(AgCl)$, it acts as a strong common ion source. For $AgCl$, $K_{sp} = [Ag^+][Cl^-] \implies 1.6 \times 10^{-10} = [Ag^+](10^{-3}) \implies [Ag^+] = 1.6 \times 10^{-7} \text{ M}$.