A weak acid () with reacts with a strong base () to form a salt (). What is the equilibrium constant — Ionic Equilibrium Chemistry Question
Question
A weak acid ($HA$) with $K_a = 10^{-4}$ reacts with a strong base ($BOH$) to form a salt ($AB$). What is the equilibrium constant for this neutralization reaction?
Answer: A
💡 Solution & Explanation
Neutralization is the reverse of hydrolysis. $K_{neutralization} = 1 / K_h$. For a WA-SB salt, $K_h = K_w / K_a = 10^{-14} / 10^{-4} = 10^{-10}$. Thus, $K_{neutralization} = 1 / 10^{-10} = 10^{10}$.
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