In the classical electrolytic preparation of Hydrogen Peroxide, a 50% solution of Sulphuric acid () — Hydrogen Chemistry Question

💡 Solution & Explanation

During the electrolysis of $50\% H_2SO_4$ at low temperatures, bisulphate ions ($HSO_4^-$) oxidize and dimerize at the anode to form Peroxodisulphuric acid ($H_2S_2O_8$). This intermediate is then extracted and hydrolyzed with water to produce $H_2SO_4$ and $H_2O_2$.