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Olefins undergo a crucial industrial process called hydroformylation. If exactly of propene () underHydrogen Chemistry Question

Question

Olefins undergo a crucial industrial process called hydroformylation. If exactly $1\text{ mole}$ of propene ($CH_3CH=CH_2$) undergoes complete hydroformylation followed by subsequent catalytic reduction, what is the final organic product and how many total moles of $H_2$ are consumed?

Answer: A

💡 Solution & Explanation

Hydroformylation reacts an olefin with $CO + H_2$ (consuming 1 mole $H_2$) to form an aldehyde with *one additional carbon* (Propene $\rightarrow$ Butanal). Subsequent reduction with another mole of $H_2$ yields the primary alcohol, Butan-1-ol. Total $H_2$ consumed = 2 moles.

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