In the synthesis of complex metal hydrides, anhydrous Lithium Hydride () is preferred as a starting β Hydrogen Chemistry Question
Question
In the synthesis of complex metal hydrides, anhydrous Lithium Hydride ($LiH$) is preferred as a starting material over Sodium Hydride ($NaH$). When $LiH$ is reacted with Aluminium Chloride ($Al_2Cl_6$) in ether, what are the exact stoichiometric products formed?
Answer: B
π‘ Solution & Explanation
Lithium hydride is relatively unreactive towards moderate $O_2$ and $Cl_2$, making it safe for synthesis. It reacts with Aluminium Chloride to form the powerful reducing agent Lithium Aluminium Hydride: $8LiH + Al_2Cl_6 \rightarrow 2LiAlH_4 + 6LiCl$.
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