Exactly of butane () undergo complete steam reforming over a Nickel catalyst at 1270 K. What is the — Hydrogen Chemistry Question

💡 Solution & Explanation

The general equation for steam reforming of alkanes is $C_nH_{2n+2} + nH_2O \rightarrow nCO + (2n+1)H_2$. For butane, $n=4$. One mole of butane produces $(2(4)+1) = 9\text{ moles}$ of $H_2$. Therefore, 2 moles of butane will produce $2 \times 9 = 18\text{ moles}$ of $H_2$.