In the planar hexagonal geometry of benzene, the bond angles are defined by the hybridization of the constituent carbon atoms. What is the value of this angle?

Question

In the planar hexagonal geometry of benzene, the $C-C-C$ bond angles are defined by the hybridization of the constituent carbon atoms. What is the value of this angle?

Prashant Kotian · Accepted Answer

Correct answer: B. Because every carbon atom in benzene utilizes strictly hybridization with no lone pairs, the molecular geometry at each center is perfectly trigonal planar, imposing a strict bond angle.

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