Complete oxidative ozonolysis ( followed by ) of an alkene gives two moles of an aldehyde of molar m β Hydrocarbons Chemistry Question
Question
Complete oxidative ozonolysis ($O_3$ followed by $H_2O_2$) of an alkene gives two moles of an aldehyde of molar mass 44 g/mol. What is the IUPAC name of the alkene?
Answer: B
π‘ Solution & Explanation
An aldehyde with molar mass 44 g/mol is acetaldehyde ($CH_3CHO$). Reversing the ozonolysis by connecting two $CH_3CH=$ fragments yields $CH_3CH=CHCH_3$, which is But-2-ene.
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