When 3,3-dimethyl-1-butene reacts with aqueous acid (), a rearranged major product is formed. What i — Hydrocarbons Chemistry Question

💡 Solution & Explanation

Protonation forms a secondary carbocation. A 1,2-methyl shift immediately occurs from the adjacent quaternary carbon to form a much more stable tertiary carbocation, which water then attacks to yield 2,3-dimethyl-2-butanol.