When n-heptane undergoes aromatization over at 773 K and 10-20 atm, what is the major benzenoid prod — Hydrocarbons Chemistry Question

💡 Solution & Explanation

Aromatization requires a minimum of 6 carbons to form the ring. n-heptane has 7 carbons; 6 cyclize into the benzenoid core, leaving the 7th as a methyl substituent, yielding toluene.