When isobutane (2-methylpropane) undergoes free radical bromination in the presence of light, what i — Hydrocarbons Chemistry Question

💡 Solution & Explanation

Bromine radicals are highly selective ($1600 : 82 : 1$ for $3^\circ : 2^\circ : 1^\circ$). They almost exclusively abstract the stable tertiary hydrogen, yielding 2-bromo-2-methylpropane (*tert*-butyl bromide).