The correct decreasing order regarding the electronegativity of the hybrid orbitals of carbon is: — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

The electronegativity of a hybrid orbital is directly proportional to its percentage of s-character. Since the $sp$ orbital has 50% s-character, it is more electronegative than $sp^2$ (33.3% s) and $sp^3$ (25% s).