In the hydrocarbon pent-2-en-4-yne, the hybridization states of the carbon atoms from to are respect — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

The structure is $CH_3-CH=CH-C \equiv CH$. Numbering from right to left gives the lowest locants to multiple bonds, but the question asks from C1 to C5 based on IUPAC naming (double bond gets preference if locants tie, but here it's 1-yne, 3-ene if numbered from right). Correct IUPAC is pent-3-en-1-yne. Assuming the visual C1-C5 sequence of $CH_3(sp^3)-CH(sp^2)=CH(sp^2)-C(sp) \equiv CH(sp)$, the order is $sp^3, sp^2, sp^2, sp, sp$.