The correct decreasing order regarding the electronegativity of the hybrid orbitals of carbon is: — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

Electronegativity of a hybrid orbital is directly proportional to its percentage of s-character. $sp$ (50% s) is more electronegative than $sp^2$ (33.3% s), which is more electronegative than $sp^3$ (25% s).