is a versatile oxidizer whose reaction pathway is dictated by pH. When oxidizing the Iodide ion (), — d and f Block Elements Chemistry Question

💡 Solution & Explanation

In acid, $MnO_4^-$ drops to $Mn^{2+}$, oxidizing $I^-$ to free molecular Iodine ($I_2$). In faintly alkaline media, $MnO_4^-$ drops only to $MnO_2$, but pushes the oxidation of $I^-$ further, generating the Iodate ion ($IO_3^-$).