Manganese can form the stable covalent compound in the oxidation state. However, its highest corresp — d and f Block Elements Chemistry Question
Question
Manganese can form the stable covalent compound $Mn_2O_7$ in the $+7$ oxidation state. However, its highest corresponding fluoride is only $MnF_4$. Why can oxygen stabilize higher oxidation states than fluorine?
Answer: C
💡 Solution & Explanation
While fluorine is the most electronegative element, oxygen's ability to form stable double bonds ($\pi$ -bonds) with the vacant $d$ -orbitals of the metal allows it to stabilize higher charge densities and extreme oxidation states (like $+7$).
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