Calculate the spin-only magnetic moment () for a divalent metal ion () belonging to a neutral transi — d and f Block Elements Chemistry Question

💡 Solution & Explanation

The neutral atom is Iron ($Z=26$), $[Ar] 3d^6 4s^2$. Ionizing to $Fe^{2+}$ removes the two $4s$ electrons, leaving $[Ar] 3d^6$. This contains exactly 4 unpaired electrons ($n=4$). Using $\mu = \sqrt{n(n+2)}$, $\mu = \sqrt{4(6)} = \sqrt{24} \approx 4.89 \text{ B.M.}$