The standard electrode potential () for the couple is highly positive, whereas it is heavily negativ — d and f Block Elements Chemistry Question
Question
The standard electrode potential ($E^\circ$) for the $Mn^{3+}/Mn^{2+}$ couple is highly positive, whereas it is heavily negative for the $Cr^{3+}/Cr^{2+}$ couple. What causes $Mn^{3+}$ to be easily reduced?
Answer: B
💡 Solution & Explanation
$Mn^{3+}$ ($d^4$) is a strong oxidizing agent because gaining an electron yields the exceptionally stable half-filled $d^5$ state. $Cr^{3+}$, on the other hand, already possesses a highly stable $t_{2g}^3$ state in an aqueous octahedral field.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes