The green manganate ion () is stable only in highly alkaline media. If the solution is acidified, it — d and f Block Elements Chemistry Question
Question
The green manganate ion ($MnO_4^{2-}$) is stable only in highly alkaline media. If the solution is acidified, it violently undergoes disproportionation. What are the final products of this disproportionation?
Answer: B
💡 Solution & Explanation
The $+6$ state is unstable in acid. The reaction is $3MnO_4^{2-} + 4H^+ \to 2MnO_4^- + MnO_2 + 2H_2O$. It simultaneously oxidizes to $+7$ (Permanganate) and reduces to $+4$ (Manganese dioxide).
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