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What is the exact equivalent weight of (Molar mass = M) when it acts as an oxidizing agent in a strod and f Block Elements Chemistry Question

Question

What is the exact equivalent weight of $KMnO_4$ (Molar mass = M) when it acts as an oxidizing agent in a strongly acidic medium?

Answer: C

💡 Solution & Explanation

In acidic media, $KMnO_4$ reduces from $Mn^{7+}$ down to $Mn^{2+}$. The balanced half-reaction involves the transfer of 5 electrons ($n=5$). Therefore, the equivalent weight is exactly $M/5$.

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