The green manganate ion () exhibits strict stability only in highly alkaline media. If the pH is low — d and f Block Elements Chemistry Question
Question
The green manganate ion ($MnO_4^{2-}$) exhibits strict stability only in highly alkaline media. If the pH is lowered into acidic or neutral territories, it violently undergoes disproportionation. What are the exact final products of this disproportionation?
Answer: B
💡 Solution & Explanation
The $+6$ state of Manganese is unstable in acid. The reaction is $3MnO_4^{2-} + 4H^+ \rightarrow 2MnO_4^- + MnO_2 + 2H_2O$. It simultaneously oxidizes to $+7$ (Permanganate) and reduces to $+4$ (Manganese dioxide precipitate).
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