Manganese can readily form the covalent green oil in the extreme oxidation state. However, its highe — d and f Block Elements Chemistry Question
Question
Manganese can readily form the covalent green oil $Mn_2O_7$ in the extreme $+7$ oxidation state. However, its highest corresponding stable fluoride is only Manganese(IV) fluoride ($MnF_4$). Why is oxygen definitively capable of stabilizing higher oxidation states than fluorine?
Answer: C
💡 Solution & Explanation
While fluorine is the most electronegative element, oxygen's unique ability to form stable $\pi$ -bonds (double bonds) with the vacant $d$ -orbitals of the metal allows it to stabilize higher charge densities and extreme oxidation states (like $+7$ and $+8$).
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