Manganese can readily form the covalent green oil in the extreme oxidation state. However, its highest corresponding stable fluoride is only Manganese(IV) fluoride (). Why is oxygen definitively capab

Question

Manganese can readily form the covalent green oil $Mn_2O_7$ in the extreme $+7$ oxidation state. However, its highest corresponding stable fluoride is only Manganese(IV) fluoride ($MnF_4$). Why is oxygen definitively capable of stabilizing higher oxidation states than fluorine?

Prashant Kotian · Accepted Answer

Correct answer: C. While fluorine is the most electronegative element, oxygen's unique ability to form stable -bonds (double bonds) with the vacant -orbitals of the metal allows it to stabilize higher charge densities and extreme oxidation states (like and ).

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