The complex is paramagnetic with 2 unpaired electrons. Its hybridisation and geometry according to V — Coordination Compounds Chemistry Question

💡 Solution & Explanation

$Ni^{2+}$ is $3d^8$. Since it has 2 unpaired electrons, no pairing occurs (weak field ligand $Cl^-$). The inner 3d orbitals are occupied, so hybridisation uses the outer 4s and 4p orbitals, yielding $sp^3$ (Tetrahedral).