A coordination compound precipitates silver chloride when treated with silver nitrate. Its molar con — Coordination Compounds Chemistry Question
Question
A coordination compound $CrCl_3 \cdot 4H_2O$ precipitates silver chloride when treated with silver nitrate. Its molar conductance corresponds to a total of two ions. What is its structural formula?
Answer: A
💡 Solution & Explanation
The molar conductance corresponds to 2 ions, meaning the complex dissociates into 1 complex cation and 1 counter anion. Thus, 1 $Cl^-$ must be outside the sphere. The formula is $[Cr(H_2O)_4Cl_2]Cl$.
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