Arrange the following complexes in decreasing order of their molar conductance in aqueous solution: (I) , (II) , (III) , (IV) .

Question

Arrange the following complexes in decreasing order of their molar conductance in aqueous solution: (I) $K_4[Fe(CN)_6]$, (II) $[Co(NH_3)_6]Cl_3$, (III) $[Pt(NH_3)_2Cl_4]$, (IV) $[Co(NH_3)_4Cl_2]Cl$.

Prashant Kotian · Accepted Answer

Correct answer: A. Molar conductance is directly proportional to the total number of ions produced in solution. (I) produces 5 ions (). (II) produces 4 ions. (IV) produces 2 ions. (III) is neutral and produces 0 ions. Order: I > II > IV > III.

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