Arrange the following complexes in decreasing order of their molar conductance in aqueous solution: — Coordination Compounds Chemistry Question
Question
Arrange the following complexes in decreasing order of their molar conductance in aqueous solution: (I) $K_4[Fe(CN)_6]$, (II) $[Co(NH_3)_6]Cl_3$, (III) $[Pt(NH_3)_2Cl_4]$, (IV) $[Co(NH_3)_4Cl_2]Cl$.
Answer: A
💡 Solution & Explanation
Molar conductance is directly proportional to the total number of ions produced in solution. (I) produces 5 ions ($4K^+, 1[Fe(CN)_6]^{4-}$). (II) produces 4 ions. (IV) produces 2 ions. (III) is neutral and produces 0 ions. Order: I > II > IV > III.
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