For identical ligands and metal oxidation state, the relative magnitudes of crystal field splitting energies in square planar (), octahedral (), and tetrahedral () complexes follow which order?

Question

For identical ligands and metal oxidation state, the relative magnitudes of crystal field splitting energies in square planar ($\Delta_{sp}$), octahedral ($\Delta_o$), and tetrahedral ($\Delta_t$) complexes follow which order?

Prashant Kotian · Accepted Answer

Correct answer: B. Square planar has the most extreme splitting due to 4 ligands heavily repelling the orbital (). Octahedral is intermediate (). Tetrahedral is weak ().

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