If (pairing energy), what will be the electronic configuration of a transition metal ion in an octah — Coordination Compounds Chemistry Question

💡 Solution & Explanation

Since the crystal field splitting energy ($\Delta_o$) is less than the pairing energy, it is energetically favorable for the 4th electron to jump into the higher $e_g$ orbital rather than pair up in the $t_{2g}$ orbital. Result is high-spin $t_{2g}^3 e_g^1$.