Consider an elementary reversible first-order reaction with forward rate constant and backward rate constant . At dynamic equilibrium, how is the thermodynamic equilibrium constant () defined kinetica

Question

Consider an elementary reversible first-order reaction $A \rightleftharpoons B$ with forward rate constant $k_f$ and backward rate constant $k_b$. At dynamic equilibrium, how is the thermodynamic equilibrium constant ($K_{eq}$) defined kinetically?

Prashant Kotian · Accepted Answer

Correct answer: D. At dynamic equilibrium, the net macroscopic rate is zero, meaning the forward rate strictly equals the reverse rate: . Rearranging this kinetic equality yields the thermodynamic ratio .

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