In the pseudo-first-order acid-catalyzed hydrolysis of an ester, reaction progress is monitored by t — Chemical Kinetics Chemistry Question
Question
In the pseudo-first-order acid-catalyzed hydrolysis of an ester, reaction progress is monitored by titrating aliquots against $NaOH$. If $V_0$, $V_t$, and $V_\infty$ are the base volumes required, what is the correct rate constant expression?
Answer: A
💡 Solution & Explanation
The total ester concentration $a$ is proportional to the total acid generated, $(V_\infty - V_0)$. The unreacted ester $(a-x)$ is proportional to the acid yet to be generated, $(V_\infty - V_t)$. Thus, $k = \frac{2.303}{t} \log\left(\frac{V_\infty - V_0}{V_\infty - V_t}\right)$.
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