For a first-order reaction, the "Average Life" () is mathematically defined as the reciprocal of the — Chemical Kinetics Chemistry Question
Question
For a first-order reaction, the "Average Life" ($T_{avg}$) is mathematically defined as the reciprocal of the decay constant ($\lambda$ or $k$). What is the exact relationship between Average Life and Half-Life ($t_{1/2}$)?
Answer: B
💡 Solution & Explanation
By definition, $T_{avg} = 1/k$. Since $t_{1/2} = 0.693/k$, isolating $k$ gives $k = 0.693/t_{1/2}$. Substituting this gives $T_{avg} = t_{1/2} / 0.693$. Because $1/0.693 \approx 1.44$, the average life is $1.44 \times t_{1/2}$.
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