In the catalytic formation of ammonia , the rate of appearance of is measured as . What is the rate — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

From stoichiometry, $-\frac{1}{3}\frac{d[H_2]}{dt} = +\frac{1}{2}\frac{d[NH_3]}{dt}$. Thus, rate of disappearance of $H_2 = \frac{3}{2} \times (2.5 \times 10^{-4}) = 3.75 \times 10^{-4} \text{ mol L}^{-1}\text{s}^{-1}$.