A chemical reaction is thoroughly logged to be exactly 50% complete in strictly and exactly 75% comp — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

The elapsed time required to destroy 75% of the initial mass ($t_{75\%}$) evaluates cleanly to precisely double the half-life ($t_{50\%}$), because $4 \text{ hours} = 2 \times 2 \text{ hours}$. This strict fractional $2\times$ time progression mapping is uniquely the mathematical signature of First Order kinetics.