If a student plots the base-10 logarithm of the rate constant () versus , what will be the exact mat — Chemical Kinetics Chemistry Question
Question
If a student plots the base-10 logarithm of the rate constant ($\log_{10} k$) versus $1/T$, what will be the exact mathematical slope of the resulting straight line?
Answer: B
💡 Solution & Explanation
Converting the natural log Arrhenius equation to base-10 requires dividing by 2.303. The equation becomes $\log_{10} k = \log_{10} A - \frac{E_a}{2.303 R} \cdot \frac{1}{T}$. Thus, the mathematical slope is rigorously $-E_a / 2.303 R$.
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