For a reaction , the rate is doubled when the concentration of B is doubled. The rate increases by a — Chemical Kinetics Chemistry Question
Question
For a reaction $A + B \rightarrow \text{Products}$, the rate is doubled when the concentration of B is doubled. The rate increases by a factor of 8 when the concentrations of both A and B are doubled. The rate law is:
Answer: B
💡 Solution & Explanation
Doubling [B] doubles the rate, so order w.r.t B is 1. Doubling both gives $2^x \times 2^1 = 8 \Rightarrow 2^x = 4 \Rightarrow x = 2$. Order w.r.t A is 2. Rate law is $k[A]^2[B]^1$.
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