In the catalytic formation of ammonia , the rate of appearance of is measured as . What is the rate — Chemical Kinetics Chemistry Question
Question
In the catalytic formation of ammonia $N_2 + 3H_2 \rightarrow 2NH_3$, the rate of appearance of $NH_3$ is measured as $2.5 \times 10^{-4} \text{ mol L}^{-1}\text{s}^{-1}$. What is the rate of disappearance of $H_2$?
Answer: C
💡 Solution & Explanation
From stoichiometry, $-\frac{1}{3}\frac{d[H_2]}{dt} = +\frac{1}{2}\frac{d[NH_3]}{dt}$. Thus, rate of disappearance of $H_2 = \frac{3}{2} \times (2.5 \times 10^{-4}) = 3.75 \times 10^{-4} \text{ mol L}^{-1}\text{s}^{-1}$.
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